Hello, python zmq_client.py -j 357 --hostname 127.0.0.1 -t 1200" should work.
Cheers
Le ven. 18 janv. 2019 à 10:13, cnspring2002 cnspring2002@aliyun.com a écrit :
Just use the sample command "python zmq_client.py -j 357 --hostname tcp:// 127.0.0.1:5500 -t 1200"
Get the error:
Traceback (most recent call last): File "zmq_client_1.py", line 155, in <module> main() File "zmq_client_1.py", line 139, in main publisher = lookup_publisher(options.hostname, options.https) File "zmq_client_1.py", line 109, in lookup_publisher socket = server.scheduler.get_publisher_event_socket() File "/usr/lib/python3.5/xmlrpc/client.py", line 1092, in __call__ return self.__send(self.__name, args) File "/usr/lib/python3.5/xmlrpc/client.py", line 1432, in __request verbose=self.__verbose File "/usr/lib/python3.5/xmlrpc/client.py", line 1134, in request return self.single_request(host, handler, request_body, verbose) File "/usr/lib/python3.5/xmlrpc/client.py", line 1146, in single_request http_conn = self.send_request(host, handler, request_body, verbose) File "/usr/lib/python3.5/xmlrpc/client.py", line 1259, in send_request self.send_content(connection, request_body) File "/usr/lib/python3.5/xmlrpc/client.py", line 1289, in send_content connection.endheaders(request_body) File "/usr/lib/python3.5/http/client.py", line 1103, in endheaders self._send_output(message_body) File "/usr/lib/python3.5/http/client.py", line 934, in _send_output self.send(msg) File "/usr/lib/python3.5/http/client.py", line 877, in send self.connect() File "/usr/lib/python3.5/http/client.py", line 849, in connect (self.host,self.port), self.timeout, self.source_address) File "/usr/lib/python3.5/socket.py", line 694, in create_connection for res in getaddrinfo(host, port, 0, SOCK_STREAM): File "/usr/lib/python3.5/socket.py", line 733, in getaddrinfo for res in _socket.getaddrinfo(host, port, family, type, proto, flags): socket.gaierror: [Errno -2] Name or service not known
I wonder for following code, why http://tcp://127.0.0.1:5500/RPC2 will finally be passed to ServerProxy? If I remove http, just tcp://127.0.0.1:5500/RPC2, it will say "OSError: unsupported XML-RPC protocol" If I remove tcp, just http://127.0.0.1:5500/RPC2, it will hang in get_publisher_event_socket
I use 2018.11 version, please suggest!!!
xmlrpc_url = "http://%s/RPC2" % (hostname) if https: xmlrpc_url = "https://%s/RPC2" % (hostname) server = xmlrpc.client.ServerProxy(xmlrpc_url) try: socket = server.scheduler.get_publisher_event_socket()
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